First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is a factor. Factorise the quadratic ...
Long considered solved, David Hilbert’s question about seventh-degree polynomials is leading researchers to a new web of mathematical connections. Success is rare in math. Just ask Benson Farb. “The ...
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